16b^2+11=2884

Solution for 16b^2+11=2884 equation:

16b^2+11=2884

We move all terms to the left:

16b^2+11-(2884)=0

We add all the numbers together, and all the variables

16b^2-2873=0

a = 16; b = 0; c = -2873;
Δ = b2-4ac
Δ = 02-4·16·(-2873)
Δ = 183872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{183872}=\sqrt{10816*17}=\sqrt{10816}*\sqrt{17}=104\sqrt{17}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-104\sqrt{17}}{2*16}=\frac{0-104\sqrt{17}}{32}
=-\frac{104\sqrt{17}}{32}
=-\frac{13\sqrt{17}}{4}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+104\sqrt{17}}{2*16}=\frac{0+104\sqrt{17}}{32}
=\frac{104\sqrt{17}}{32}
=\frac{13\sqrt{17}}{4}
$